Charlie and Adam have some stickers in the ratio of 5 : 7.
When Charlie gives away 48 stickers,
the ratio of the stickers becomes 3 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
5 x 5 = 25 u |
7 x 5 = 35 u |
Change |
- 48 |
No change |
After |
3 x 7 = 21 u |
5 x 7 = 35 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 7 and 5.
LCM of 7 and 5 = 35
Number of stickers that Charlie gives away
= 25 u - 21 u
= 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Number of stickers that they have at first
= 25 u + 35 u
= 60 u
= 60 x 12
= 720
(b)
Number of stickers that they have in the end
= 21 u + 35 u
= 56 u
= 56 x 12
= 672
Answer(s): (a) 720; (b) 672