Bryan and Adam have some stickers in the ratio of 5 : 8.
When Bryan gives away 99 stickers,
the ratio of the stickers becomes 4 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
5 x 7 = 35 u |
8 x 7 = 56 u |
Change |
- 99 |
No change |
After |
4 x 8 = 32 u |
7 x 8 = 56 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 8 and 7.
LCM of 8 and 7 = 56
Number of stickers that Bryan gives away
= 35 u - 32 u
= 3 u
3 u = 99
1 u = 99 ÷ 3 = 33
Number of stickers that they have at first
= 35 u + 56 u
= 91 u
= 91 x 33
= 3003
(b)
Number of stickers that they have in the end
= 32 u + 56 u
= 88 u
= 88 x 33
= 2904
Answer(s): (a) 3003; (b) 2904