Bryan and Adam have some stickers in the ratio of 7 : 5.
When Bryan gives away 41 stickers,
the ratio of the stickers becomes 3 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
7 x 8 = 56 u |
5 x 8 = 40 u |
Change |
- 41 |
No change |
After |
3 x 5 = 15 u |
8 x 5 = 40 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 5 and 8.
LCM of 5 and 8 = 40
Number of stickers that Bryan gives away
= 56 u - 15 u
= 41 u
41 u = 41
1 u = 41 ÷ 41 = 1
Number of stickers that they have at first
= 56 u + 40 u
= 96 u
= 96 x 1
= 96
(b)
Number of stickers that they have in the end
= 15 u + 40 u
= 55 u
= 55 x 1
= 55
Answer(s): (a) 96; (b) 55