Bryan and Adam have some stickers in the ratio of 5 : 4.
When Bryan gives away 98 stickers,
the ratio of the stickers becomes 3 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
5 x 2 = 10 u |
4 x 2 = 8 u |
Change |
- 98 |
No change |
After |
3 x 1 = 3 u |
8 x 1 = 8 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 4 and 8.
LCM of 4 and 8 = 8
Number of stickers that Bryan gives away
= 10 u - 3 u
= 7 u
7 u = 98
1 u = 98 ÷ 7 = 14
Number of stickers that they have at first
= 10 u + 8 u
= 18 u
= 18 x 14
= 252
(b)
Number of stickers that they have in the end
= 3 u + 8 u
= 11 u
= 11 x 14
= 154
Answer(s): (a) 252; (b) 154