Charlie and Adam have some stickers in the ratio of 3 : 2.
When Charlie gives away 93 stickers,
the ratio of the stickers becomes 3 : 4.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
3 x 2 = 6 u |
2 x 2 = 4 u |
Change |
- 93 |
No change |
After |
3 x 1 = 3 u |
4 x 1 = 4 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 2 and 4.
LCM of 2 and 4 = 4
Number of stickers that Charlie gives away
= 6 u - 3 u
= 3 u
3 u = 93
1 u = 93 ÷ 3 = 31
Number of stickers that they have at first
= 6 u + 4 u
= 10 u
= 10 x 31
= 310
(b)
Number of stickers that they have in the end
= 3 u + 4 u
= 7 u
= 7 x 31
= 217
Answer(s): (a) 310; (b) 217