Adam and Charlie have some stickers in the ratio of 5 : 2.
When Adam gives away 98 stickers,
the ratio of the stickers becomes 4 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
5 x 3 = 15 u |
2 x 3 = 6 u |
Change |
- 98 |
No change |
After |
4 x 2 = 8 u |
3 x 2 = 6 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 2 and 3.
LCM of 2 and 3 = 6
Number of stickers that Adam gives away
= 15 u - 8 u
= 7 u
7 u = 98
1 u = 98 ÷ 7 = 14
Number of stickers that they have at first
= 15 u + 6 u
= 21 u
= 21 x 14
= 294
(b)
Number of stickers that they have in the end
= 8 u + 6 u
= 14 u
= 14 x 14
= 196
Answer(s): (a) 294; (b) 196