Adam and Charlie have some stickers in the ratio of 5 : 4.
When Adam gives away 15 stickers,
the ratio of the stickers becomes 5 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
5 x 2 = 10 u |
4 x 2 = 8 u |
Change |
- 15 |
No change |
After |
5 x 1 = 5 u |
8 x 1 = 8 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 4 and 8.
LCM of 4 and 8 = 8
Number of stickers that Adam gives away
= 10 u - 5 u
= 5 u
5 u = 15
1 u = 15 ÷ 5 = 3
Number of stickers that they have at first
= 10 u + 8 u
= 18 u
= 18 x 3
= 54
(b)
Number of stickers that they have in the end
= 5 u + 8 u
= 13 u
= 13 x 3
= 39
Answer(s): (a) 54; (b) 39