Adam and Charlie have some stickers in the ratio of 5 : 2.
When Adam gives away 58 stickers,
the ratio of the stickers becomes 3 : 7.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
5 x 7 = 35 u |
2 x 7 = 14 u |
Change |
- 58 |
No change |
After |
3 x 2 = 6 u |
7 x 2 = 14 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 2 and 7.
LCM of 2 and 7 = 14
Number of stickers that Adam gives away
= 35 u - 6 u
= 29 u
29 u = 58
1 u = 58 ÷ 29 = 2
Number of stickers that they have at first
= 35 u + 14 u
= 49 u
= 49 x 2
= 98
(b)
Number of stickers that they have in the end
= 6 u + 14 u
= 20 u
= 20 x 2
= 40
Answer(s): (a) 98; (b) 40