Bryan and Adam have some stickers in the ratio of 5 : 6.
When Bryan gives away 60 stickers,
the ratio of the stickers becomes 5 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
5 x 4 = 20 u |
6 x 4 = 24 u |
Change |
- 60 |
No change |
After |
5 x 3 = 15 u |
8 x 3 = 24 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 6 and 8.
LCM of 6 and 8 = 24
Number of stickers that Bryan gives away
= 20 u - 15 u
= 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Number of stickers that they have at first
= 20 u + 24 u
= 44 u
= 44 x 12
= 528
(b)
Number of stickers that they have in the end
= 15 u + 24 u
= 39 u
= 39 x 12
= 468
Answer(s): (a) 528; (b) 468