Adam and Charlie have some stickers in the ratio of 8 : 3.
When Adam gives away 93 stickers,
the ratio of the stickers becomes 3 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
8 x 5 = 40 u |
3 x 5 = 15 u |
Change |
- 93 |
No change |
After |
3 x 3 = 9 u |
5 x 3 = 15 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 3 and 5.
LCM of 3 and 5 = 15
Number of stickers that Adam gives away
= 40 u - 9 u
= 31 u
31 u = 93
1 u = 93 ÷ 31 = 3
Number of stickers that they have at first
= 40 u + 15 u
= 55 u
= 55 x 3
= 165
(b)
Number of stickers that they have in the end
= 9 u + 15 u
= 24 u
= 24 x 3
= 72
Answer(s): (a) 165; (b) 72