Bryan and Adam have some stickers in the ratio of 7 : 4.
When Bryan gives away 42 stickers,
the ratio of the stickers becomes 7 : 6.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
7 x 3 = 21 u |
4 x 3 = 12 u |
Change |
- 42 |
No change |
After |
7 x 2 = 14 u |
6 x 2 = 12 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 4 and 6.
LCM of 4 and 6 = 12
Number of stickers that Bryan gives away
= 21 u - 14 u
= 7 u
7 u = 42
1 u = 42 ÷ 7 = 6
Number of stickers that they have at first
= 21 u + 12 u
= 33 u
= 33 x 6
= 198
(b)
Number of stickers that they have in the end
= 14 u + 12 u
= 26 u
= 26 x 6
= 156
Answer(s): (a) 198; (b) 156