Adam and Bryan have some stickers in the ratio of 4 : 3.
When Adam gives away 32 stickers,
the ratio of the stickers becomes 4 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
4 x 5 = 20 u |
3 x 5 = 15 u |
Change |
- 32 |
No change |
After |
4 x 3 = 12 u |
5 x 3 = 15 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 3 and 5.
LCM of 3 and 5 = 15
Number of stickers that Adam gives away
= 20 u - 12 u
= 8 u
8 u = 32
1 u = 32 ÷ 8 = 4
Number of stickers that they have at first
= 20 u + 15 u
= 35 u
= 35 x 4
= 140
(b)
Number of stickers that they have in the end
= 12 u + 15 u
= 27 u
= 27 x 4
= 108
Answer(s): (a) 140; (b) 108