Bryan and Charlie have some stickers in the ratio of 7 : 4.
When Bryan gives away 42 stickers,
the ratio of the stickers becomes 7 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
7 x 5 = 35 u |
4 x 5 = 20 u |
Change |
- 42 |
No change |
After |
7 x 4 = 28 u |
5 x 4 = 20 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 4 and 5.
LCM of 4 and 5 = 20
Number of stickers that Bryan gives away
= 35 u - 28 u
= 7 u
7 u = 42
1 u = 42 ÷ 7 = 6
Number of stickers that they have at first
= 35 u + 20 u
= 55 u
= 55 x 6
= 330
(b)
Number of stickers that they have in the end
= 28 u + 20 u
= 48 u
= 48 x 6
= 288
Answer(s): (a) 330; (b) 288