Charlie and Bryan have some stickers in the ratio of 6 : 7.
When Charlie gives away 56 stickers,
the ratio of the stickers becomes 4 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Bryan |
Before |
6 x 5 = 30 u |
7 x 5 = 35 u |
Change |
- 56 |
No change |
After |
4 x 7 = 28 u |
5 x 7 = 35 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 7 and 5.
LCM of 7 and 5 = 35
Number of stickers that Charlie gives away
= 30 u - 28 u
= 2 u
2 u = 56
1 u = 56 ÷ 2 = 28
Number of stickers that they have at first
= 30 u + 35 u
= 65 u
= 65 x 28
= 1820
(b)
Number of stickers that they have in the end
= 28 u + 35 u
= 63 u
= 63 x 28
= 1764
Answer(s): (a) 1820; (b) 1764