Adam and Bryan have some stickers in the ratio of 3 : 4.
When Adam gives away 33 stickers,
the ratio of the stickers becomes 3 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
3 x 2 = 6 u |
4 x 2 = 8 u |
Change |
- 33 |
No change |
After |
3 x 1 = 3 u |
8 x 1 = 8 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 4 and 8.
LCM of 4 and 8 = 8
Number of stickers that Adam gives away
= 6 u - 3 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Number of stickers that they have at first
= 6 u + 8 u
= 14 u
= 14 x 11
= 154
(b)
Number of stickers that they have in the end
= 3 u + 8 u
= 11 u
= 11 x 11
= 121
Answer(s): (a) 154; (b) 121