Adam and Bryan have some stickers in the ratio of 6 : 5.
When Adam gives away 88 stickers,
the ratio of the stickers becomes 2 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
6 x 3 = 18 u |
5 x 3 = 15 u |
Change |
- 88 |
No change |
After |
2 x 5 = 10 u |
3 x 5 = 15 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 5 and 3.
LCM of 5 and 3 = 15
Number of stickers that Adam gives away
= 18 u - 10 u
= 8 u
8 u = 88
1 u = 88 ÷ 8 = 11
Number of stickers that they have at first
= 18 u + 15 u
= 33 u
= 33 x 11
= 363
(b)
Number of stickers that they have in the end
= 10 u + 15 u
= 25 u
= 25 x 11
= 275
Answer(s): (a) 363; (b) 275