Charlie and Bryan have some stickers in the ratio of 6 : 7.
When Charlie gives away 51 stickers,
the ratio of the stickers becomes 3 : 4.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Bryan |
Before |
6 x 4 = 24 u |
7 x 4 = 28 u |
Change |
- 51 |
No change |
After |
3 x 7 = 21 u |
4 x 7 = 28 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 7 and 4.
LCM of 7 and 4 = 28
Number of stickers that Charlie gives away
= 24 u - 21 u
= 3 u
3 u = 51
1 u = 51 ÷ 3 = 17
Number of stickers that they have at first
= 24 u + 28 u
= 52 u
= 52 x 17
= 884
(b)
Number of stickers that they have in the end
= 21 u + 28 u
= 49 u
= 49 x 17
= 833
Answer(s): (a) 884; (b) 833