Bryan and Charlie have some stickers in the ratio of 5 : 4.
When Bryan gives away 80 stickers,
the ratio of the stickers becomes 5 : 6.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
5 x 3 = 15 u |
4 x 3 = 12 u |
Change |
- 80 |
No change |
After |
5 x 2 = 10 u |
6 x 2 = 12 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 4 and 6.
LCM of 4 and 6 = 12
Number of stickers that Bryan gives away
= 15 u - 10 u
= 5 u
5 u = 80
1 u = 80 ÷ 5 = 16
Number of stickers that they have at first
= 15 u + 12 u
= 27 u
= 27 x 16
= 432
(b)
Number of stickers that they have in the end
= 10 u + 12 u
= 22 u
= 22 x 16
= 352
Answer(s): (a) 432; (b) 352