Bryan and Adam have some stickers in the ratio of 7 : 3.
When Bryan gives away 63 stickers,
the ratio of the stickers becomes 7 : 6.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
7 x 2 = 14 u |
3 x 2 = 6 u |
Change |
- 63 |
No change |
After |
7 x 1 = 7 u |
6 x 1 = 6 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 3 and 6.
LCM of 3 and 6 = 6
Number of stickers that Bryan gives away
= 14 u - 7 u
= 7 u
7 u = 63
1 u = 63 ÷ 7 = 9
Number of stickers that they have at first
= 14 u + 6 u
= 20 u
= 20 x 9
= 180
(b)
Number of stickers that they have in the end
= 7 u + 6 u
= 13 u
= 13 x 9
= 117
Answer(s): (a) 180; (b) 117