Charlie and Bryan have some stickers in the ratio of 3 : 2.
When Charlie gives away 60 stickers,
the ratio of the stickers becomes 7 : 6.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Bryan |
Before |
3 x 3 = 9 u |
2 x 3 = 6 u |
Change |
- 60 |
No change |
After |
7 x 1 = 7 u |
6 x 1 = 6 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 2 and 6.
LCM of 2 and 6 = 6
Number of stickers that Charlie gives away
= 9 u - 7 u
= 2 u
2 u = 60
1 u = 60 ÷ 2 = 30
Number of stickers that they have at first
= 9 u + 6 u
= 15 u
= 15 x 30
= 450
(b)
Number of stickers that they have in the end
= 7 u + 6 u
= 13 u
= 13 x 30
= 390
Answer(s): (a) 450; (b) 390