Adam and Charlie have some stickers in the ratio of 7 : 2.
When Adam gives away 46 stickers,
the ratio of the stickers becomes 5 : 8.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
7 x 4 = 28 u |
2 x 4 = 8 u |
Change |
- 46 |
No change |
After |
5 x 1 = 5 u |
8 x 1 = 8 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 2 and 8.
LCM of 2 and 8 = 8
Number of stickers that Adam gives away
= 28 u - 5 u
= 23 u
23 u = 46
1 u = 46 ÷ 23 = 2
Number of stickers that they have at first
= 28 u + 8 u
= 36 u
= 36 x 2
= 72
(b)
Number of stickers that they have in the end
= 5 u + 8 u
= 13 u
= 13 x 2
= 26
Answer(s): (a) 72; (b) 26