Charlie and Bryan have some stickers in the ratio of 4 : 5.
When Charlie gives away 70 stickers,
the ratio of the stickers becomes 2 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Bryan |
Before |
4 x 3 = 12 u |
5 x 3 = 15 u |
Change |
- 70 |
No change |
After |
2 x 5 = 10 u |
3 x 5 = 15 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 5 and 3.
LCM of 5 and 3 = 15
Number of stickers that Charlie gives away
= 12 u - 10 u
= 2 u
2 u = 70
1 u = 70 ÷ 2 = 35
Number of stickers that they have at first
= 12 u + 15 u
= 27 u
= 27 x 35
= 945
(b)
Number of stickers that they have in the end
= 10 u + 15 u
= 25 u
= 25 x 35
= 875
Answer(s): (a) 945; (b) 875