Adam and Charlie have some stickers in the ratio of 8 : 7.
When Adam gives away 19 stickers,
the ratio of the stickers becomes 3 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
8 x 5 = 40 u |
7 x 5 = 35 u |
Change |
- 19 |
No change |
After |
3 x 7 = 21 u |
5 x 7 = 35 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 7 and 5.
LCM of 7 and 5 = 35
Number of stickers that Adam gives away
= 40 u - 21 u
= 19 u
19 u = 19
1 u = 19 ÷ 19 = 1
Number of stickers that they have at first
= 40 u + 35 u
= 75 u
= 75 x 1
= 75
(b)
Number of stickers that they have in the end
= 21 u + 35 u
= 56 u
= 56 x 1
= 56
Answer(s): (a) 75; (b) 56