Adam and Bryan have some stickers in the ratio of 5 : 7.
When Adam buys another 10 stickers,
the ratio of the stickers becomes 5 : 6.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
5 x 6 = 30 u |
7 x 6 = 42 u |
Change |
+ 10 |
No change |
After |
5 x 7 = 35 u |
6 x 7 = 42 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 7 and 6.
LCM of 7 and 6 = 42
Number of stickers that Bryan buys
= 35 u - 30 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Number of stickers that they have at first
= 30 u + 42 u
= 72 u
= 72 x 2
= 144
(b)
Number of stickers that they have in the end
= 35 u + 42 u
= 77 u
= 77 x 2
= 154
Answer(s): (a) 144; (b) 154