Adam and Bryan have some stickers in the ratio of 8 : 7.
When Adam buys another 60 stickers,
the ratio of the stickers becomes 5 : 4.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
8 x 4 = 32 u |
7 x 4 = 28 u |
Change |
+ 60 |
No change |
After |
5 x 7 = 35 u |
4 x 7 = 28 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 7 and 4.
LCM of 7 and 4 = 28
Number of stickers that Charlie buys
= 35 u - 32 u
= 3 u
3 u = 60
1 u = 60 ÷ 3 = 20
Number of stickers that they have at first
= 32 u + 28 u
= 60 u
= 60 x 20
= 1200
(b)
Number of stickers that they have in the end
= 35 u + 28 u
= 63 u
= 63 x 20
= 1260
Answer(s): (a) 1200; (b) 1260