Adam and Bryan have some stickers in the ratio of 2 : 3.
When Adam buys another 12 stickers,
the ratio of the stickers becomes 4 : 5.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
2 x 5 = 10 u |
3 x 5 = 15 u |
Change |
+ 12 |
No change |
After |
4 x 3 = 12 u |
5 x 3 = 15 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 3 and 5.
LCM of 3 and 5 = 15
Number of stickers that Adam buys
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of stickers that they have at first
= 10 u + 15 u
= 25 u
= 25 x 6
= 150
(b)
Number of stickers that they have in the end
= 12 u + 15 u
= 27 u
= 27 x 6
= 162
Answer(s): (a) 150; (b) 162