Adam and Bryan have some stickers in the ratio of 7 : 6.
When Adam buys another 30 stickers,
the ratio of the stickers becomes 5 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
7 x 1 = 7 u |
6 x 1 = 6 u |
Change |
+ 30 |
No change |
After |
5 x 2 = 10 u |
3 x 2 = 6 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 6 and 3.
LCM of 6 and 3 = 6
Number of stickers that Bryan buys
= 10 u - 7 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of stickers that they have at first
= 7 u + 6 u
= 13 u
= 13 x 10
= 130
(b)
Number of stickers that they have in the end
= 10 u + 6 u
= 16 u
= 16 x 10
= 160
Answer(s): (a) 130; (b) 160