Adam and Bryan have some stickers in the ratio of 3 : 8.
When Adam buys another 14 stickers,
the ratio of the stickers becomes 2 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
3 x 3 = 9 u |
8 x 3 = 24 u |
Change |
+ 14 |
No change |
After |
2 x 8 = 16 u |
3 x 8 = 24 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 8 and 3.
LCM of 8 and 3 = 24
Number of stickers that Adam buys
= 16 u - 9 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
Number of stickers that they have at first
= 9 u + 24 u
= 33 u
= 33 x 2
= 66
(b)
Number of stickers that they have in the end
= 16 u + 24 u
= 40 u
= 40 x 2
= 80
Answer(s): (a) 66; (b) 80