Adam and Bryan have some stickers in the ratio of 5 : 6.
When Adam buys another 51 stickers,
the ratio of the stickers becomes 4 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
5 x 1 = 5 u |
6 x 1 = 6 u |
Change |
+ 51 |
No change |
After |
4 x 2 = 8 u |
3 x 2 = 6 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 6 and 3.
LCM of 6 and 3 = 6
Number of stickers that Adam buys
= 8 u - 5 u
= 3 u
3 u = 51
1 u = 51 ÷ 3 = 17
Number of stickers that they have at first
= 5 u + 6 u
= 11 u
= 11 x 17
= 187
(b)
Number of stickers that they have in the end
= 8 u + 6 u
= 14 u
= 14 x 17
= 238
Answer(s): (a) 187; (b) 238