Adam and Bryan have some stickers in the ratio of 7 : 8.
When Adam buys another 14 stickers,
the ratio of the stickers becomes 7 : 4.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
7 x 1 = 7 u |
8 x 1 = 8 u |
Change |
+ 14 |
No change |
After |
7 x 2 = 14 u |
4 x 2 = 8 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 8 and 4.
LCM of 8 and 4 = 8
Number of stickers that Bryan buys
= 14 u - 7 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
Number of stickers that they have at first
= 7 u + 8 u
= 15 u
= 15 x 2
= 30
(b)
Number of stickers that they have in the end
= 14 u + 8 u
= 22 u
= 22 x 2
= 44
Answer(s): (a) 30; (b) 44