Adam and Bryan have some stickers in the ratio of 7 : 8.
When Adam buys another 35 stickers,
the ratio of the stickers becomes 3 : 2.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
7 x 1 = 7 u |
8 x 1 = 8 u |
Change |
+ 35 |
No change |
After |
3 x 4 = 12 u |
2 x 4 = 8 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 8 and 2.
LCM of 8 and 2 = 8
Number of stickers that Adam buys
= 12 u - 7 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of stickers that they have at first
= 7 u + 8 u
= 15 u
= 15 x 7
= 105
(b)
Number of stickers that they have in the end
= 12 u + 8 u
= 20 u
= 20 x 7
= 140
Answer(s): (a) 105; (b) 140