Adam and Bryan have some stickers in the ratio of 5 : 4.
When Adam buys another 10 stickers,
the ratio of the stickers becomes 5 : 2.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
5 x 1 = 5 u |
4 x 1 = 4 u |
Change |
+ 10 |
No change |
After |
5 x 2 = 10 u |
2 x 2 = 4 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 4 and 2.
LCM of 4 and 2 = 4
Number of stickers that Adam buys
= 10 u - 5 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Number of stickers that they have at first
= 5 u + 4 u
= 9 u
= 9 x 2
= 18
(b)
Number of stickers that they have in the end
= 10 u + 4 u
= 14 u
= 14 x 2
= 28
Answer(s): (a) 18; (b) 28