Adam and Bryan have some stickers in the ratio of 8 : 3.
When Adam buys another 95 stickers,
the ratio of the stickers becomes 7 : 2.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
8 x 2 = 16 u |
3 x 2 = 6 u |
Change |
+ 95 |
No change |
After |
7 x 3 = 21 u |
2 x 3 = 6 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 3 and 2.
LCM of 3 and 2 = 6
Number of stickers that Adam buys
= 21 u - 16 u
= 5 u
5 u = 95
1 u = 95 ÷ 5 = 19
Number of stickers that they have at first
= 16 u + 6 u
= 22 u
= 22 x 19
= 418
(b)
Number of stickers that they have in the end
= 21 u + 6 u
= 27 u
= 27 x 19
= 513
Answer(s): (a) 418; (b) 513