Adam and Bryan have some stickers in the ratio of 2 : 5.
When Adam buys another 42 stickers,
the ratio of the stickers becomes 4 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
2 x 3 = 6 u |
5 x 3 = 15 u |
Change |
+ 42 |
No change |
After |
4 x 5 = 20 u |
3 x 5 = 15 u |
(a)
The number of stickers that Adam has remains unchanged.
Make the number of stickers that Adam has the same using LCM of 5 and 3.
LCM of 5 and 3 = 15
Number of stickers that Bryan buys
= 20 u - 6 u
= 14 u
14 u = 42
1 u = 42 ÷ 14 = 3
Number of stickers that they have at first
= 6 u + 15 u
= 21 u
= 21 x 3
= 63
(b)
Number of stickers that they have in the end
= 20 u + 15 u
= 35 u
= 35 x 3
= 105
Answer(s): (a) 63; (b) 105