Adam and Bryan have some stickers in the ratio of 4 : 7.
When Adam buys another 28 stickers,
the ratio of the stickers becomes 2 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Bryan |
Before |
4 x 3 = 12 u |
7 x 3 = 21 u |
Change |
+ 28 |
No change |
After |
2 x 7 = 14 u |
3 x 7 = 21 u |
(a)
The number of stickers that Bryan has remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 7 and 3.
LCM of 7 and 3 = 21
Number of stickers that Charlie buys
= 14 u - 12 u
= 2 u
2 u = 28
1 u = 28 ÷ 2 = 14
Number of stickers that they have at first
= 12 u + 21 u
= 33 u
= 33 x 14
= 462
(b)
Number of stickers that they have in the end
= 14 u + 21 u
= 35 u
= 35 x 14
= 490
Answer(s): (a) 462; (b) 490