Adam and Bryan have some stickers in the ratio of 3 : 2.
When Adam buys another 70 stickers,
the ratio of the stickers becomes 8 : 3.
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Charlie |
Before |
3 x 3 = 9 u |
2 x 3 = 6 u |
Change |
+ 70 |
No change |
After |
8 x 2 = 16 u |
3 x 2 = 6 u |
(a)
The number of stickers that Charlie has remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 2 and 3.
LCM of 2 and 3 = 6
Number of stickers that Bryan buys
= 16 u - 9 u
= 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Number of stickers that they have at first
= 9 u + 6 u
= 15 u
= 15 x 10
= 150
(b)
Number of stickers that they have in the end
= 16 u + 6 u
= 22 u
= 22 x 10
= 220
Answer(s): (a) 150; (b) 220