Adam has green and blue stickers in the ratio of 1 : 4.
When 51 blue stickers are replaced with the same number of green stickers,
the ratio of the number of green and blue stickers will be 2 : 5
How many stickers are there altogether?
|
Green |
Blue |
Total |
Before |
1 x 7 = 7 u |
4 x 7 = 28 u |
5 x 7 = 35 u |
Change |
+ 51 |
- 51 |
|
After |
2 x 5 = 10 u |
5 x 5 = 25 u |
7 x 5 = 35 u |
When 51 blue stickers are replaced with the same number of green stickers, the total number of stickers remains unchanged.
Make the total number of stickers the same using the LCM of 5 and 7.
LCM of 5 and 7 = 35
Number of blue stickers that is replaced by green stickers
= 10 u - 7 u
= 3 u
3 u = 51
1 u = 51 ÷ 3 = 17
Total number of stickers
= 35 u
= 35 x 17
= 595
Answer(s): 595