Adam has 200 green stickers, red stickers and blue stickers.
60% of the stickers are red.
50% of the remaining stickers are green.
The rest are blue stickers.
- How many blue stickers are there?
- How many less green stickers than red stickers?
Red |
Green |
Blue |
3 u |
2 u |
|
50% |
50% |
|
2 u x 50% = 1 u
|
2 u x 50% = 1 u
|
60% =
60100 =
35 Total number of stickers = 5 u
Number of red stickers = 3 u
Number of green and blue stickers
= 5 u - 3 u
= 2 u
5 u = 200
1 u = 200 ÷ 5 = 40
(a)
Percent of remaining stickers that are blue
= 100% - 50%
= 50%
Number of blue stickers
= 50% x 2 u
= 0.5 x 2 u
= 1 u
= 1 x 40
= 40
(b)
Number of green stickers
= 50% x 2 u
= 0.5 x 2 u
= 1 u
Number of red stickers = 3 u
Number of less green stickers than red stickers
= 3 u - 1 u
= 2 u
= 2 x 40
= 80
Answer(s): (a) 40; (b) 80