Adam has 150 blue stickers, red stickers and green stickers.
60% of the stickers are red.
40% of the remaining stickers are blue.
The rest are green stickers.
- How many green stickers are there?
- How many less blue stickers than red stickers?
Red |
Blue |
Green |
3 u |
2 u |
|
40% |
60% |
|
2 u x 40% = 0.8 u
|
2 u x 60% = 1.2 u
|
60% =
60100 =
35 Total number of stickers = 5 u
Number of red stickers = 3 u
Number of blue and green stickers
= 5 u - 3 u
= 2 u
5 u = 150
1 u = 150 ÷ 5 = 30
(a)
Percent of remaining stickers that are green
= 100% - 40%
= 60%
Number of green stickers
= 60% x 2 u
= 0.6 x 2 u
= 1.2 u
= 1.2 x 30
= 36
(b)
Number of blue stickers
= 40% x 2 u
= 0.4 x 2 u
= 0.8 u
Number of red stickers = 3 u
Number of less blue stickers than red stickers
= 3 u - 0.8 u
= 2.2 u
= 2.2 x 30
= 66
Answer(s): (a) 36; (b) 66