Adam has 200 green stickers, blue stickers and red stickers.
60% of the stickers are blue.
40% of the remaining stickers are green.
The rest are red stickers.
- How many red stickers are there?
- How many less green stickers than blue stickers?
Blue |
Green |
Red |
3 u |
2 u |
|
40% |
60% |
|
2 u x 40% = 0.8 u
|
2 u x 60% = 1.2 u
|
60% =
60100 =
35 Total number of stickers = 5 u
Number of blue stickers = 3 u
Number of green and red stickers
= 5 u - 3 u
= 2 u
5 u = 200
1 u = 200 ÷ 5 = 40
(a)
Percent of remaining stickers that are red
= 100% - 40%
= 60%
Number of red stickers
= 60% x 2 u
= 0.6 x 2 u
= 1.2 u
= 1.2 x 40
= 48
(b)
Number of green stickers
= 40% x 2 u
= 0.4 x 2 u
= 0.8 u
Number of blue stickers = 3 u
Number of less green stickers than blue stickers
= 3 u - 0.8 u
= 2.2 u
= 2.2 x 40
= 88
Answer(s): (a) 48; (b) 88