Adam has 320 green stickers, red stickers and blue stickers.
40% of the stickers are red.
50% of the remaining stickers are green.
The rest are blue stickers.
- How many blue stickers are there?
- How many less green stickers than red stickers?
Red |
Green |
Blue |
2 u |
3 u |
|
50% |
50% |
|
3 u x 50% = 1.5 u
|
3 u x 50% = 1.5 u
|
40% =
40100 =
25 Total number of stickers = 5 u
Number of red stickers = 2 u
Number of green and blue stickers
= 5 u - 2 u
= 3 u
5 u = 320
1 u = 320 ÷ 5 = 64
(a)
Percent of remaining stickers that are blue
= 100% - 50%
= 50%
Number of blue stickers
= 50% x 3 u
= 0.5 x 3 u
= 1.5 u
= 1.5 x 64
= 96
(b)
Number of green stickers
= 50% x 3 u
= 0.5 x 3 u
= 1.5 u
Number of red stickers = 2 u
Number of less green stickers than red stickers
= 2 u - 1.5 u
= 0.5 u
= 0.5 x 64
= 32
Answer(s): (a) 96; (b) 32