Adam has 100 green stickers, red stickers and blue stickers.
60% of the stickers are red.
60% of the remaining stickers are green.
The rest are blue stickers.
- How many blue stickers are there?
- How many less green stickers than red stickers?
Red |
Green |
Blue |
3 u |
2 u |
|
60% |
40% |
|
2 u x 60% = 1.2 u
|
2 u x 40% = 0.8 u
|
60% =
60100 =
35 Total number of stickers = 5 u
Number of red stickers = 3 u
Number of green and blue stickers
= 5 u - 3 u
= 2 u
5 u = 100
1 u = 100 ÷ 5 = 20
(a)
Percent of remaining stickers that are blue
= 100% - 60%
= 40%
Number of blue stickers
= 40% x 2 u
= 0.4 x 2 u
= 0.8 u
= 0.8 x 20
= 16
(b)
Number of green stickers
= 60% x 2 u
= 0.6 x 2 u
= 1.2 u
Number of red stickers = 3 u
Number of less green stickers than red stickers
= 3 u - 1.2 u
= 1.8 u
= 1.8 x 20
= 36
Answer(s): (a) 16; (b) 36