Adam has 200 blue stickers, green stickers and red stickers.
75% of the stickers are green.
30% of the remaining stickers are blue.
The rest are red stickers.
- How many red stickers are there?
- How many less blue stickers than green stickers?
Green |
Blue |
Red |
3 u |
1 u |
|
30% |
70% |
|
1 u x 30% = 0.3 u
|
1 u x 70% = 0.7 u
|
75% =
75100 =
34 Total number of stickers = 4 u
Number of green stickers = 3 u
Number of blue and red stickers
= 4 u - 3 u
= 1 u
4 u = 200
1 u = 200 ÷ 4 = 50
(a)
Percent of remaining stickers that are red
= 100% - 30%
= 70%
Number of red stickers
= 70% x 1 u
= 0.7 x 1 u
= 0.7 u
= 0.7 x 50
= 35
(b)
Number of blue stickers
= 30% x 1 u
= 0.3 x 1 u
= 0.3 u
Number of green stickers = 3 u
Number of less blue stickers than green stickers
= 3 u - 0.3 u
= 2.7 u
= 2.7 x 50
= 135
Answer(s): (a) 35; (b) 135