Adam has 320 red stickers, blue stickers and green stickers.
75% of the stickers are blue.
50% of the remaining stickers are red.
The rest are green stickers.
- How many green stickers are there?
- How many less red stickers than blue stickers?
Blue |
Red |
Green |
3 u |
1 u |
|
50% |
50% |
|
1 u x 50% = 0.5 u
|
1 u x 50% = 0.5 u
|
75% =
75100 =
34 Total number of stickers = 4 u
Number of blue stickers = 3 u
Number of red and green stickers
= 4 u - 3 u
= 1 u
4 u = 320
1 u = 320 ÷ 4 = 80
(a)
Percent of remaining stickers that are green
= 100% - 50%
= 50%
Number of green stickers
= 50% x 1 u
= 0.5 x 1 u
= 0.5 u
= 0.5 x 80
= 40
(b)
Number of red stickers
= 50% x 1 u
= 0.5 x 1 u
= 0.5 u
Number of blue stickers = 3 u
Number of less red stickers than blue stickers
= 3 u - 0.5 u
= 2.5 u
= 2.5 x 80
= 200
Answer(s): (a) 40; (b) 200