Adam has 100 green stickers, blue stickers and red stickers.
60% of the stickers are blue.
30% of the remaining stickers are green.
The rest are red stickers.
- How many red stickers are there?
- How many less green stickers than blue stickers?
Blue |
Green |
Red |
3 u |
2 u |
|
30% |
70% |
|
2 u x 30% = 0.6 u
|
2 u x 70% = 1.4 u
|
60% =
60100 =
35 Total number of stickers = 5 u
Number of blue stickers = 3 u
Number of green and red stickers
= 5 u - 3 u
= 2 u
5 u = 100
1 u = 100 ÷ 5 = 20
(a)
Percent of remaining stickers that are red
= 100% - 30%
= 70%
Number of red stickers
= 70% x 2 u
= 0.7 x 2 u
= 1.4 u
= 1.4 x 20
= 28
(b)
Number of green stickers
= 30% x 2 u
= 0.3 x 2 u
= 0.6 u
Number of blue stickers = 3 u
Number of less green stickers than blue stickers
= 3 u - 0.6 u
= 2.4 u
= 2.4 x 20
= 48
Answer(s): (a) 28; (b) 48