Adam has 280 green stickers, blue stickers and red stickers.
40% of the stickers are blue.
50% of the remaining stickers are green.
The rest are red stickers.
- How many red stickers are there?
- How many less green stickers than blue stickers?
Blue |
Green |
Red |
2 u |
3 u |
|
50% |
50% |
|
3 u x 50% = 1.5 u
|
3 u x 50% = 1.5 u
|
40% =
40100 =
25 Total number of stickers = 5 u
Number of blue stickers = 2 u
Number of green and red stickers
= 5 u - 2 u
= 3 u
5 u = 280
1 u = 280 ÷ 5 = 56
(a)
Percent of remaining stickers that are red
= 100% - 50%
= 50%
Number of red stickers
= 50% x 3 u
= 0.5 x 3 u
= 1.5 u
= 1.5 x 56
= 84
(b)
Number of green stickers
= 50% x 3 u
= 0.5 x 3 u
= 1.5 u
Number of blue stickers = 2 u
Number of less green stickers than blue stickers
= 2 u - 1.5 u
= 0.5 u
= 0.5 x 56
= 28
Answer(s): (a) 84; (b) 28