Adam has 320 green stickers, blue stickers and red stickers.
75% of the stickers are blue.
40% of the remaining stickers are green.
The rest are red stickers.
- How many red stickers are there?
- How many less green stickers than blue stickers?
Blue |
Green |
Red |
3 u |
1 u |
|
40% |
60% |
|
1 u x 40% = 0.4 u
|
1 u x 60% = 0.6 u
|
75% =
75100 =
34 Total number of stickers = 4 u
Number of blue stickers = 3 u
Number of green and red stickers
= 4 u - 3 u
= 1 u
4 u = 320
1 u = 320 ÷ 4 = 80
(a)
Percent of remaining stickers that are red
= 100% - 40%
= 60%
Number of red stickers
= 60% x 1 u
= 0.6 x 1 u
= 0.6 u
= 0.6 x 80
= 48
(b)
Number of green stickers
= 40% x 1 u
= 0.4 x 1 u
= 0.4 u
Number of blue stickers = 3 u
Number of less green stickers than blue stickers
= 3 u - 0.4 u
= 2.6 u
= 2.6 x 80
= 208
Answer(s): (a) 48; (b) 208