Adam has 100 blue stickers and red stickers.
80% of them are blue stickers and the rest are red stickers.
When Adam gives away some blue stickers,
60% of the remaining stickers are blue stickers.
How many stickers does Adam give away?
|
Blue |
Red |
Before |
4 x 2 = 8 u |
1 x 2 = 2 u |
Change |
- ? |
No change |
After |
3 x 1 = 3 u |
2 x 1 = 2 u |
80% =
80100 =
4560% =
60100 =
35 The number of red stickers remains unchanged.
Make the number of red stickers the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Total number of stickers at first
= 8 u + 2 u
= 10 u
10 u = 100
1 u = 100 ÷ 10 = 10
Number of stickers that Adam gives away
= 8 u - 3 u
= 5 u
= 5 x 10
= 50
Answer(s): 50