Bryan and Adam have 210 stickers.
Bryan has 20% as many stickers as Adam.
- How many stickers must Adam give to Bryan so that both will have the same number of stickers?
- How many stickers does each of them have in the end?
| |
Bryan |
Adam |
Total |
| Before |
1 u |
5 u |
6 u |
| Change |
+ ? |
- ? |
|
| After |
3 u |
3 u |
6 u |
(a)
20% =
20100 =
15 Number of stickers that Bryan has = 1 u
Number of stickers that Adam has = 5 u
Total number of stickers
= 1 u + 5 u
= 6 u
6 u = 210
1 u = 210 ÷ 6 = 35
Number of stickers that each boy will have in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Adam must give to Bryan
= 5 u - 3 u
= 2 u
= 2 x 35
= 70
(b)
Number of stickers that each of them have in the end
= 210 ÷ 2
= 105
Answer(s): (a) 70; (b) 105
