Adam has some green stickers and blue stickers.
If 246 green stickers are removed, 90% of the stickers will be blue stickers.
If 38 green stickers are removed, 25% of the stickers will be blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 246 |
9 u |
27 u + 38 |
9 u |
Change |
- 246 |
No change |
- 38 |
No change |
After |
1x1 = 1 u |
9x1 = 9 u |
3x9 = 27 u |
1x9 = 9 u |
(a)
90% =
90100 =
91025% =
25100 =
14Scenario 1 Fraction of the stickers that are green in the end
= 1 -
910 =
110 Scenario 2
Fraction of the stickers that are green in the end
= 1 -
14 =
34 The number of blue stickers remains unchanged in both scenarios.
LCM of 9 and 1 = 9
1 u + 246 = 27 u + 38
27 u - 1 u = 246 - 38
26 u = 208
1 u = 208 ÷ 26 = 8
Number of green stickers
= 1 u + 246
= 1 x 8 + 246
= 8 + 246
= 254
(b)
Number of blue stickers
= 9 u
= 9 x 8
= 72
Answer(s): (a) 254; (b) 72